9t^2-50t+25=0

Solution for 9t^2-50t+25=0 equation:

9t^2-50t+25=0

a = 9; b = -50; c = +25;
Δ = b2-4ac
Δ = -502-4·9·25
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-40}{2*9}=\frac{10}{18}
=5/9
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+40}{2*9}=\frac{90}{18}
=5
$